Given that (x + 3) is a factor of 6x3 - bx2 +18 find the value of b
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x+3 is a factor of 6x3...
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Answer:
x=(-3).... Substitute value of x
6(-3)³ -b(-3)² +18=0
6(-27) -b(9) +18=0
-162 -9b + 18=0
-144-9b=0
-144/9=b
b=(-6)
Hope it helps you
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