Question

Given that (x-√5) is factor of the polynomial x3-3√5x2-5x+15√5. Find all the zeros of the polynomial.

Answer 1

x³ - 3√5x² - 5x + 15√5
= x³ - √5x² - 2√5x² + 10x - 15x + 15√5
= x²(x - √5) -2√5x( x - √5) -15(x - √5)
= {x² - 2√5x - 15 }(x - √5)
= {x² +√5x - 3√5x - 15}(x - √5)
= {x (x + √5) -3(x + √5)} (x - √5)
= (x -3)(x + √5)(x - √5)

hence, (x -3) and (x + √5) are two another factors of given polynomial.

Answer 2

Answer:

Step-by-step explanation: