Question

If one of the zeroes of the polynomial (k-1)x^2+Kx+1 is -3, find k

Answer 1

Let f (x)=(k-1)x^2+kx+1
Given -3 is one of the zeros of f (x)

F (-3)=(k-1)(-3)^2-3k+1=0
=>(k-1)9-3k+1=0
=>9k-9-3k+1=0
=>6k-8=0
=>6k=8
=>k=8/6
=>k=4/3

Answer 2

One of the zero is -3 (x=-3)

(k-1)x² + kx + 1 = 0

(k-1) (-3)² + k(-3) + 1 = 0

(k-1) (9) - 3k + 1 = 0

9k-9-3k+1 = 0

6k - 8 = 0

6k = 8

k = 8/6

k = 4/3

Hope it helps