Question

Given that x and y are real numbers satisfying the following equation
$x + xy + y = 2 + \sqrt{3} \: and \: {x}^{2} + {y}^{2} = 6 \: \: than \: the \: value \: of \: |x + y + 1| = a + \sqrt{b} then \: product \: of \: a \: and \: b \: is$
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Answer 1

Step-by-step explanation:

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