Question

Given that x = R cos0, y = R sine and 0 = wt, where R and are constants. Find the value of [(dx/dt)² + (dy/dt)²]​

Answer 1

Explanation:

here is ur answers

.

.

.

.

.

.

.

.

.

hope it helps u

Answer 2

Given,

• x = RCosθ
• y = RSinθ
• θ=wt
• R and w are constants

To find,

(dx/dt)² + (dy/dt)²

Solution,

Differentiating the equation x = RCos(wt), we have

                dx = -R*w*Sin(wt)*dt                     eq(1)

Differentiating the equation y = RSinθ, we have

                dy = R*w*Cos(wt)*dt                    eq(2)

Squaring both equations and adding them,

                    (dx/dt)² + (dy/dt)² =  R²*w²

Therefore, the value of     (dx/dt)² + (dy/dt)² is  R²*w².