Question

Given the a and b are the root of the equation x2+5x-3=0,find the quadratic equation whose roots are 1/a2 and 1/b2

Answer 1

Step-by-step explanation:

here a and b are roots of x2+5x-3=0

a+b=-5

a×b=-3

1/a2+1/b2=a2+b2/a2b2 =

a2+b2=(a+b)2-2ab

=25+6

=31

1/a2b2=1/9

here the equation is x2-31x+1/9=0

or9x2-279x+1= 0