Question

Given the date in the form of dd-mm-yyyy, write a program to find the day of the year.

Answer 1

Answer:

# include <stdio.h>

# include <conio.h>

void main()

{

int month[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

char week[7][10] ;

int date, mon, year, i, r, s = 0 ;

clrscr();

strcpy(week[0], "Sunday") ;

strcpy(week[1], "Monday") ;

strcpy(week[2], "Tuesday") ;

strcpy(week[3], "Wednesday") ;

strcpy(week[4], "Thursday") ;

strcpy(week[5], "Friday") ;

strcpy(week[6], "Saturday") ;

printf("Enter a valid date (dd/mm/yyyy) : ") ;

scanf("%d / %d / %d", &date, &mon, &year) ;

if( (year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0)) )

month[1] = 29 ;

for(i = 0 ; i < mon - 1 ; i++)

s = s + month[i] ;

s = s + (date + year + (year / 4) - 2) ;

s = s % 7 ;

printf("\nThe day is : %s", week[s]) ;

getch() ;

}

Explanation:

Here’s a C program to find the day of the given date with output and proper explanation. The program takes as input a formatted date and returns the day on that date. This program makes use of single and multidimensional arrays, for loop and string function - strcpy() (string copy).