Question

Given the magnitude and direction of the force acting on a stone of mass 0.1 kg (a) just after it is dropped from the window of a stationary train (b) just after it is dropped from the window of a train running at a constant velocity of 36 km//hr (c) just after it is droped from the window of a train accelerating with 1 ms^(-2) (d) lying on the floor of a trin which is accelerating with 1 ms^(-2) the stone being at rest relative to the train . Neglect the resistance of air throuhout .

Answer 1

Answer:

Part a)

When stone is dropped from stationary train

$F = 1 N$

Direction : Downwards

b)

When train is running at constant speed and stone is dropped

$F = 0.1 \times 10 = 1 N$

Direction : Downwards

c)

When train is running at constant acceleration and stone is dropped

$F = 0.1 \times 10 = 1 N$

Direction : Downwards

d)

When stone is placed on the floor of the train and remains at rest

$F = 0.1 N$

Direction : In the direction of motion of train

Explanation:

As we know that when an object is dropped from some height then net force is due to gravity on it

a) When it is dropped from stationary train

So we have

$F = mg$

$F = 0.1 \times 10 = 1 N$

Direction : Downwards

b)

When train is running at constant speed and stone is dropped from the window then net force on it is due to gravity

it is given as

$F = mg$

$F = 0.1 \times 10 = 1 N$

Direction : Downwards

c)

When train is running at constant acceleration and stone is dropped from the window then net force on it is due to gravity

it is given as

$F = mg$

$F = 0.1 \times 10 = 1 N$

Direction : Downwards

d)

When stone is placed on the floor of the train and remains at rest with respect to floor then we have

$F = ma$

$F = 0.1 (1)$

$F = 0.1 N$

Direction : In the direction of motion of train

#Learn

Topic : Newton's 2nd Law

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