Question

Given the polymers (i) Nylon-66; (ii) Buna-S; (iii) Polythene,
arrange these in increasing order of their inter-molecular
forces (lower to higher)
(a) (i) > (ii) > (iii) (b) (ii) > (iii) > (i)
(c) (ii) < (iii) < (i) (d) (iii) < (i) < (ii)

Answer 1

Explanation:

The correct answer is option (d) (iii) < (i) < (ii)

Answer 2

Increasing order of their inter-molecular  forces in the following compounds are as follows.

Buna -S < Polythene < Nylon 6,6.

Correct answer - "c"

Step by step explanation:

The polymers  can be divided on the basis of molecular powers such as vander waal forces, hydrogen bonding and dipole interactions.

They are Elastomers, Fibres, Thermoplastics and thermosetting polymers.

• Elastomers: These are  having elastic nature and low intermolecular forces.

        Example - Natural rubber

• Thermoplastics: These have intermediate intermolecular interactions between elastomers and polythene fibres.

       Example - Polyethene.

• Fibres:They have strong hydrogen bond and  dipole dipole interaction in between polymer chains.

        Example, - Nylon 6,6

• Thermosetting polymers: These are changed their structure while on heating.

       Example - Bakelite.

Therefore, Increasing order of their inter-molecular  forces in the following compounds are as follows.

Buna -S < Polythene < Nylon 6,6.

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