Given the rate of investment is I (t) = 2t 1/3, where 't' is time. Suppose the initial capital stock , K0 is 25 . Find the amount of capital accumulation during the time intervals (0,1) and (1,3).
Answers
Answered by
0
Subscribe to Nick Eh 30
Answered by
0
In this question we will apply the concept of integration as follows :
K∫l(t) dt
K∫2t^1/3 dt
= 2K∫t^1/3
= 2K[3/4t^4/3]
We need the intervals [0,1] and [1,3]
[0,1]
25 × 2{ [3/4 × 1^4/3] - [3/4 × 0^4/3]}
50(3/4 - 0)
= 37.5
[1,3]
50{[3/4 × 3^4/3] - [3/4 × 1^4/3]}
50{ 3.245 - 3/4}
= 50 × 2.495
= 124.75
Similar questions