Given the reaction, N2 + 2O2→ 2NO2, 14 grams of nitrogen gas will yield approximately 46 grams of nitrogen dioxide.
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Answered by
1
Answer:
N
2
+2O
2
→2NO
2
As per reaction, it is clear that 28 g ( 1 mol ) of N
2
gas produces the 92 g (2 mol ) of NO
2
,
7 g of N
2
=
28
7
=
4
1
=0.25 moles.
Now , 0.25 moles of N
2
will produce the 0.5 moles of NO
2
,
At STP, the molar volume of any gas is 22.4 L.
Hence,
273
1×22.4
=
300
0.9×V
so V = 27.35 L for 1 mol of NO
2
so for 0.5 mol of NO
2
=
2
27.35
=13.7 L
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