Question

Given the value of $\Delta H$ = 177.9 kJ and $\Delta S$ = 160.4 JK⁻¹ mol⁻¹. For the reaction $CaCO_3(s) \longrightarrow CaO(s) + CO_2(g)$ at 298 K, the free energy change per mole would be :
(a) + 130.1 kJ
(b) – 130.1 kJ
(c) – 4.90 kJ
(d) + 4.90 kJ

Answer 1

Hello Friend

The answer of u r question is

Option.a

Thank you

Answer 2

Heya Dude!

Option is (a) + 130.1 kJ

Hopes help ya