given triangle ABC congruent to triangle pqr of a b a point P Q is equals to 1 by 3 then find Triangles find area of triangle ABC upon Triangle pqr
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We know if two triangle, say ABC and PQR, have the same area, then
area of triangle ABC/area of triangle PQR = AB2/PQ2 = BC2/QR2 = AC2/PR2
Applying this formula here, we get
81/169 = 7.22/PR2
81 * PR2 = 169 * 7.22
81 * PR2 = 169 * 51.84
=> PR2 = 8760.96/81
PR2 = 108.16
=> PR = root 108.16 = 10.4 cms
Therefore length of PR = 10.4 cms
area of triangle ABC/area of triangle PQR = AB2/PQ2 = BC2/QR2 = AC2/PR2
Applying this formula here, we get
81/169 = 7.22/PR2
81 * PR2 = 169 * 7.22
81 * PR2 = 169 * 51.84
=> PR2 = 8760.96/81
PR2 = 108.16
=> PR = root 108.16 = 10.4 cms
Therefore length of PR = 10.4 cms
Answered by
1
Answer:since the triangles are congruent(similar) to each other, we calculate the linear scale factor(lsf) on respective edges of the triangle which gives 1:3,Thus the area relationship of the two congruent triangles is found by squaring the lsf which gives 1:9,thus area of triangle ABC upon triangle PQR is 1/9.
Step-by-step explanation:
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