Question

Given triangle abc is similar to triangle def such that al:dm=3:7, where al and dm are medians of triangle abc and triangle def respectievely, then ar (def):ar(abc) is

Answer 1

Answer:

9:49

Step-by-step explanation:

.......

......... by theorem of areas

Answer 2

The required ratio is 9:49.

Step-by-step explanation:

Since we have given that

Ratio of AL : DM = 3:7

Where AL and DM are medians of triangle ABC and DEF resp.

So, According to "Area similarity", we get that

$\dfrac{Ar(ABC)}{Ar(DFE)}=\dfrac{AL^2}{DM^2}=\dfrac{3^2}{7^2}=\dfrac{9}{49}$

Hence, the required ratio is 9:49.

# learn more:

Given ∆ABC ~ ∆DEF such that AL : DM = 3:7, where AL and DM are they medians of ∆ABC and ∆DEF respectively, then ar(∆DEF): ar(∆ABC) is​

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