GIVEN triangle ABC is similar to triangle PQR, if AB/PQ =1/3 ,then find ar of triangle ABC/ar of triangle PQR
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Hi ,
It is given that ,
∆ABC ~ ∆PQR ,
And
AB / PQ = 1/3 ---( 1 )
Now ,
( area ∆ABC ) / ( ∆PQR ) = AB²/PQ²
= ( AB/PQ )²
= ( 1/3 )²
= 1/9
I hope this helps you.
: )
It is given that ,
∆ABC ~ ∆PQR ,
And
AB / PQ = 1/3 ---( 1 )
Now ,
( area ∆ABC ) / ( ∆PQR ) = AB²/PQ²
= ( AB/PQ )²
= ( 1/3 )²
= 1/9
I hope this helps you.
: )
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