given tringle abc and triangle pqr is similar of ab/pq = 1/3 then find the area of triangle abc/pqr
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ar(∆ABC)/ar(∆PQR)=(AB/PQ)^2 (ncert theorem6.6)
ar(∆ABC)/ar(∆PQR)=(1/3)^2
ar(∆ABC)/ar(∆PQR)=1/9
ar(∆ABC)/ar(∆PQR)=(1/3)^2
ar(∆ABC)/ar(∆PQR)=1/9
Ananya1992:
thnk u
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hlo..sis this is your answer
hope it helps you
hope it helps you
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