Given two different prime numbers p and q, find the number of different divisors of the number
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Correct option is C
C6 For P
m & Q
n, the number of divisors is (m+1)(n+1).
n, the number of divisors is (m+1)(n+1).Consider, P
n, the number of divisors is (m+1)(n+1).Consider, P 2 Q
Qhere, m=2,n=1
Qhere, m=2,n=1Thus the number of divisors is (2+1)(1+1)=3×2=6
Qhere, m=2,n=1Thus the number of divisors is (2+1)(1+1)=3×2=6Was this answer helpful?
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