Question

Given v=0.6-0.3t(in SI units). Then the initial velocity and acceleration are a) 0.3 ms-l,0.6 ms2 b) 0.6 ms,-0.3 ms c)-0.3 ms', 0.6 ms2 d)-0.6 ms,0.3 ms2​

Answer 1

Answer:

Given v=(0.6)-(0.3)t

Initially, t=0

So put 0 in the Given equation you get v = 0.6,

Now differentiate the above equation w.r.t time,

You will get dv/dt = -(0.3),

But dv/dt is acceleration, therefore you get a = -(0.3), and note that acceleration is time independent and thus it is constant at all times

Hope this helped ;-)