given values are log 2 and log 3 find the value of log 36
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your answer is as follows
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Log36
=log6^2
(logx^m=mlogx)
=2log6
=2(log3×2)
(logxy=logx+logy)
=2(log3+log2)
=2log3+2log2
Thus log36=2log3+2log2
=log6^2
(logx^m=mlogx)
=2log6
=2(log3×2)
(logxy=logx+logy)
=2(log3+log2)
=2log3+2log2
Thus log36=2log3+2log2
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