Math, asked by mrunalisawant9754, 7 months ago

Given (x-1)^2 +3 = 2x+1, find the value of a constant term.

Answers

Answered by 71811221
0

Answer:

3

Step-by-step explanation:

x^2+1+2x-2x+3-1=0

constant 3

Answered by RejinRaj
0

Step-by-step explanation:

(x-1)^2 +3 = 2x+1

x² - 2x + 1 + 3 = 2x + 1

x² - 4x + 3 = 0

(x -3)(x-1) = 0

from this we get x = 3 & 1

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