Math, asked by yuvraj99975, 9 months ago

Given - x^2-3x+1=0 . Find x^5+1/x^5 ..​

Answers

Answered by Anonymous
1

Step-by-step explanation:

x² - 3x + 1 = 0

x² + 1 = 3x

x + 1/x = 3

x² + 1/x² = (3)² - 2 = 9 - 2

x² + 1/x² = 7 -------(1)

x³ + 1/x³ + 3(x + 1/x) = 27

x³ + 1/x³ + 3(3) = 27

x³ + 1/x³ = 27 - 9 = 18 -------(2)

from equation (1) × (2)

(x² + 1/x²) × (x³ + 1/x³) = 7 × 18

x^5 + 1/x + x + 1/x^5 = 126

x^5 + 1/x^5 + (x + 1/x) = 126

x^5 + 1/x^5 + 3 = 126

x^5 + 1/x^5 = 123

I hope it will help you

Answered by ITzRithik
1

Answer:

x^5 + 1/x^5 = 123

Hope this helps mate

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