Given, X+y=20 ,Y+Z=25 ,Z+X=19, Find. X,Y,Z
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Answered by
0
Answer:
x+y=20 (1)
y=20-x
y+z=25
put the value of y in it
20-x+z=25
-x+z=25-20
-x+z=5
x+z=19 (a)
adding them we get
2z=24
z=24/2 =12
put the value in (a)
x+12=19
x=19-12=7
put the value of x in (1)
7+y=20
y=20-7=13
Answer x=7, y=13, z=12
Answered by
0
Answer:
Step-by-step explanation: Let, x+y=20 ..........(i)
y+z=25 ..........(ii)
z+x=19 ...........(iii)
now, (i)+(ii)+(iii)=>
x+y+y+z+z+x=20+25+19
=>2x+2y+2z=64
=>2(x+y+z)=64
=>x+y+z=64/2=32
therefore, x+y+z=32
=>x=32-(y+z)
=>x=32-25 [from (ii)]
=>x=7
y=32-(z+x)
=>y=32-19 [from (iii)]
=>y=13
z=32-(x+y)
=>z=32-20 [from (i)]
=>z=12
Hope, it will help you
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