Given x+y+z=15 if 9,x,y,z, a are in A.P. while
1 1 1 5
+
X Y Z 3
if 9,X, Y, Z, a are in H.P., then the value of a will be
(A)]
(C)3
(B)2
(D) 9
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(i). x1+y1+z1=35........(ii). if a,x,y,z are in A.P. Then, x,y,z are in A.P. ∴2y=x+z......(iii). ⇒ 2y+y=15........... comparing (iii) and (i).
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