Question

Given,

x³+12x/6x²+8 = y³+27y/9y²+27.

Using componendo and dividendo find x:y.​

Answer 1

Answer:

⭐ Correct Question ⭐

➡X³+12x / 6x²+8 = Y³+27y / 9y²+27

⭐ Solution ⭐

➡Use the componendo and dividendo

=> (x³+12x+6x^2+8)/(x³+12x-6x^2-8) = (y³+27y+9y²+27)/ (y³+27y-9y²-27)

✏ The numerators are in the form

(a³+b³+3a²b+3ab²) and denominators are in the form (a³- b^3 -3a²b+3ab²).

=> [a³+b³+3a²b+3ab² = (a+b)³] and

[a³-b³-3a²b +3ab² = (ab)³]

=> (x+2)³/(x-2)³ = (y+3)³/(y-3)³

✏ take cube root on both sides we get,

=> (x+2)/(x-2) = (y+3)/(y-3)

✏Again apply componendo and dividendo rule!

=>(x+2+x-2)/(x+2-x+2)=(y+3+y-3)/(y+3-y +3)

=> 2x/4 = 2y/6

=> x/2= y/3

=> x/y = 2/3

➡ Hence, the value is

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Step-by-step explanation:

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Answer 2

Answer:

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