Giveng A 10 kg block slides without acceleration down a rough inclined plane making an angle of 20° with the horizontal Calculate the work done over a distance of 12 m when the inclination of the plane is increased to 30°
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Given: Mass of block = 10kg
Initial inclination = 20°
Final inclination = 30°
Distance = 12cm
To find: Work done
Solution:
- Friction is the hindrance that is offered to the motion of the body.
Coefficient of friction μ = tanθ
μ = tan20°
Acceleration of the block down the inclination = gSinθ - μgCosθ
a = gSin30° - tan20°(gCos30°)
= 10Sin30° - tan20°( 10 × Cos30°)
= 1.81 ms⁻²
The acceleration down the inclination is 1.81 ms⁻².
Force = mass × acceleration
= 10×1.81 N
= 18.1 N
Work done over a distance of 12m when the inclination of the plane is increased to 30° = Force × distance
= 18.1 × 12
= 217.2 Joule
- The coefficient of friction is the measure of the amount of interaction between the two surfaces related to friction between two surfaces
- The coefficient of friction value will help in determining the roughness of the surface.
- When the force applied to the body causes the displacement, then the work is said to be done.
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