Question

Gives that √2 is a zero of cubic polynomial 6x^3 + √2x^2 - 10x - 4√2, find its other two zeroes.


Class 10

Proper solution needed

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Answer 1

(i)

$=> x = - \frac{2\sqrt{2}}{3}$

Multiply and divide by $\sqrt{2}$

$=>-\frac{2\sqrt{2}}{3} *\frac{\sqrt{2}}{\sqrt{2}}$

$=> -\frac{4}{3\sqrt{2}}$

Therefore, the values of x:

$=> \boxed{x = -\frac{4}{3\sqrt{2}}, x = -\frac{1}{\sqrt{2}}}$