Chemistry, asked by joycebabu05, 4 months ago

gives the overall order of a reactio
Examples:
Zero order
Pt
1st order
2nd order
2NH3 1130 K> N2 + 3H, Rate = k[NH,lº =k
sunlight
H₂ + Ch → 2HCl; Rate = k[H]°[Cl]° = k
2N205 → 4NO2 + O2; Rate = k[N,Os
NH.NO, - →N+ 2H,0; Rate = k[NH.NO,
2NO, - →2NO+O, Rate = k[NO,
H+1, - → 2HI:
Rate = k[Hz][12]
2NO+02 -> 2NO,
Rate = k[NO]?[O
2NO + Cl2 → 2NOCI; Rate = k[NO]-[Cl]
CHỊCHO »CH + CO; Rate = k[CH,CHO]3/2
balanced chemical equation never gives us a true picture of how a reaction takes pla
mpleted in one step. The reactions taking place in one step are called elementary
elementary reactions (called mechanisms) gives us the products, the reactions as
is equal to
3rd order
Fractional order
Order of a reaction can be 0, 1, 2, 3 and even a fraction.​

Answers

Answered by starwinambili
2

Explanation:

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Answered by fenisebastian
1

For zero order reaction,

rate = rate constant k

& [A]=−kt+[A

o

]

$$(Rate=k[A]^\hat{0})$$

Given 2NH

3

(g)

⟶N

2

(g)

+3H

2

(g)

k=rate=0.1atm

⇒[NH

3

]=3atm,t=0,

⇒[N

2

]=x

⇒[H

2

]=3x

Total moles= 3−2x+x+3x=3+2x

Concentration of NH

3

at t=10,

⇒[NH

3

]=(−0.1×10)+3

=−1+3=2atm

∴3−2x=2

⇒3−2=2x

⇒2x=1

⇒x=0.5

∴ Total pressure= 3+2x=3+2(0.5)

=3+1

=4atm .

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