Giving reason in each case, show that each of the following numbers is
irrational.
(a) 4+√5
(b) -3+√6
(c) 5√7
(d) −3√8
(e) 2/√5
(f) 4/√3
Answers
Answered by
5
Step-by-step explanation:
Let as assume 4+√5 is rational
4+√5=a/b. (a,b are co primes)
√5=a-4b/b
RHS:a-4b/b is a rational
LHS:√5is irrational
so,our conctraduces that 4+√5is irrational
Answered by
14
Answer:
now , we know that a , b and 4 all are integers . so we can write it as -
√5 = integers . all integers are rational no.' s also , so.
√5 = rational no. but it is proved that √5 is an irrational no. so our supposition is wrong .
hence , 4 + √5 is and irrational no. regards
Similar questions
Social Sciences,
4 months ago
Hindi,
4 months ago
Math,
4 months ago
Science,
9 months ago
Social Sciences,
9 months ago
History,
1 year ago
Social Sciences,
1 year ago