Glycerine flows steadily through a horizontal tube of length 1.5m and radius 1.0 cm. if the amount of glycerine collected per second at one end is 4.0 xx 10^(-3) kg s^(-1), what is the pressuer difference between the two ends of the tube? (density of glycerine = 1.3xx10^(3)kgm^(-3) and viscosity of glycerine =0.83Ns m^(-2)).
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Length of the horizontal tube l = 1.5 mRadius of the tube r = 1 cm = 0.01 mDiameter of the tube d = 2r = 0.02 mGlycerine is flowing at a rate of 4.0 × 10–3 kg s–1 .M = 4.0 × 10–3 kg s–1 According to Poiseville’s formula we have the relation for the rate of flow: V = πpr4/8ηlWhere p is the pressure difference between the two ends of the tubep = V8ηl/πr4
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