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A box contains 12 balls out of which x are black. If one ball is drawn at random from the
box, what is the probability that it will be a black ball?
If 6 more black balls are put in the box, the probability of drawing a black ball is now
double of what it was before. Find x.
Answers
Answered by
1
Answer:
Total number of balls = 12
Let the number of black balls be x.
P(drawing a black ball) =
It is given that 6 more black balls are put in the box.
Now, we have:
Total number of balls = 18
Number of black balls = x + 6
P (drawing a black ball) =
Therefore, we have:
Answered by
6
Explanation:
Initially, total number of balls =12
No. of black balls =x
So, P(black ball) =12x
If 6 more black balls are added, total number of balls =12+6=18
NO. of black balls =x+6
P(black ball) = 18x+6
Given the probability of drawing a black ball is now double of what it was before
So, 122x=18(x+6)
6x=18(x+6)
3x=x+62x=6x=3
So, the number of black balls present initially =3.
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