Math, asked by DANGERADITYA3616, 1 month ago

GO THROUGH THE ATTACHED IMAGE..​

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Answered by amritachhetri912
4

Answer:

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Step-by-step explanation:

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years

Answered by jubedabegum87355
29

Answer:

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Step-by-step explanation:

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