Question

Good evening Brainliacs!!

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Please solve my question,


$\frac{81 \times {3}^{2x} }{ {3}^{3} } = 1$

Find the value of Mr. X xD


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Answer 1

$\frac{81 \times {3}^{2x} }{ {3}^{3} } = 1$

$\implies\frac{3^{4} \times {3}^{2x} }{ {3}^{3} } = 1$

$\implies \frac{ 3^{4+2x} }{ {3}^{3} } = 1$

$\implies 3^{4+2x-3}=3^{0}$

=> $ 3^{2x+1}=3^{0}$

=> $2x+1 = 0$

We know that

$a^{m}=a^{n} then m = n$

=> 2x = -1

=> x = -1/2

••••

Answer 2

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$\sf{\underline{Solution:}}$


$\frac{81 \times 3^{2x} }{3 ^{3} } = 1$

$\frac{3 ^{4} \times 3 ^{2x} }{3 ^{3} } = 1$

$\frac{3 ^{4 + 2x} }{3 ^{3} } = 1$

$3^{4 + 2x - 3} = 3°$

$3 ^{2x + 1} = 3°$

$2x + 1 = 0$

$x = - \frac{1}{2}$


$\sf{\underline{Therefore,}}$

$\sf{The\:value\:of\:'x'\:is}$ $- \frac{1}{2}$


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