good evening everyone ✨
can you all please help me with this question ✨☺️
Attachments:
Answers
Answered by
4
Answer:
Hope it's help u lakshita And Good night
Step-by-step explanation:
(i)
In AAMC and ABMD.
M is the mid-point of AB AM = BM
LAMC = ZBMD (Vertically opp. angles) CM= MD (Given)
. AAMC ABMD (SAS test of congruence)
(ii)
AAMC ABMD (1)
: BD = CA (CPCT) ZBDM = LACM (CPCT)
1.e. ZBDC = LACE
. BD || CA. (Alternate angle theorem) . ZCBD+ ZBCA= 180°
(Sum of interior angles between parallel lines is 180°)
+ ZCBD+90° = 180°
ZCBD = 180° – 90
.. ZDBC = 90°
(iii)
In ABC and AACB, we have
BD=CA from (1)
ZDBC = ZACH (Each 90°) BC = BC (Common side) ADBC AACB (SAS test of congruence)
(iv)
. CD= AB
+ CM = DM =
·· M is the midpoint of CD
. CM = 1/2CD
CM =1/2AB
Answered by
4
Step-by-step explanation:
VERY GOOD MORNING MATE...☺❣
Similar questions