Question

good evening everyone ✨
can you all please help me with this question ✨☺️​

Answer 1

Answer:

Hope it's help u lakshita And Good night

Step-by-step explanation:

(i)

In AAMC and ABMD.

M is the mid-point of AB AM = BM

LAMC = ZBMD (Vertically opp. angles) CM= MD (Given)

. AAMC ABMD (SAS test of congruence)

(ii)

AAMC ABMD (1)

: BD = CA (CPCT) ZBDM = LACM (CPCT)

1.e. ZBDC = LACE

. BD || CA. (Alternate angle theorem) . ZCBD+ ZBCA= 180°

(Sum of interior angles between parallel lines is 180°)

+ ZCBD+90° = 180°

ZCBD = 180° – 90

.. ZDBC = 90°

(iii)

In ABC and AACB, we have

BD=CA from (1)

ZDBC = ZACH (Each 90°) BC = BC (Common side) ADBC AACB (SAS test of congruence)

(iv)

. CD= AB

+ CM = DM =

·· M is the midpoint of CD

. CM = 1/2CD

CM =1/2AB

Answer 2

Step-by-step explanation:

VERY GOOD MORNING MATE...☺❣