Question

Good evening everyone please answer this in the form of essay or poem. Topics (any 1) :-
1.The hardest challenge brought out the best in me
2. I did not miss the school in the last two months because...
*I WILL DEFINITELY MARK BRAINLIEST
*DO NOT TAKE HELP FROM GOOGLE
* Answers should be relevant​
[ RELATED TO COVID 19 ]​

Answer 1

Explanation:

Since, the stone is dropped, its initial horizontal velocity is equal to the velocity og the bus which is, ux = 60 km/h = 16.67 m/s Its initial vertical velocity is, u y = 0 The height through which the stone falls is, h = 1.96 m Using, S = ut + ½ at 2 => 1.96 = 0 + ½ (9.8)(t 2 ) => t = 0.63 s Horizontal distance moved by the stone in this time is, X = u x t = (16.67)(0.63) = 10.5 m The path of the stone can be found as follows: X = u x t = 16.67t Y = u y t + ½ at 2 = (1/2)(9.8)t 2 = 4.9t 2 Using the above two equations the position of the stone at any instant can be determined.