Question

good evening gys

find area of triangle whoose side is 26cm,30cm,28cm.by using heron's formula​

Answer 1

Correct Question:-

Find the area of Triangle whose sides are 26 cm , 30 cm & 28 cm.

AnswEr:-

Area is 336 cm².

Step by Step Explanation:-

Given :-

Sides of the triangle are = 26cm , 30cm & 28 cm.

To Find :-

Area of Triangle

$\rule{150}3$

Explanation:-

By using Heron's Formula:-

$:\implies\sf\; \sqrt{s(s - a)(s - b)(s - c)}$

Here, s is semiperimeter

$:\implies\sf\; s = \dfrac{ a + b + c}{2}$

Sides are 26 cm ,30cm & 28 cm

$:\implies\sf\; s = \dfrac{ 26 + 30 + 28}{2}$

$:\implies\sf\;s =\dfrac{82}{2}$

$:\implies\large\boxed{\sf{\red{s = 42\; cm}}}$

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Now, Finding the area of Triangle

$:\implies\sf\; \sqrt{ 42(42 - 26)(42 - 28)(42 - 30)}$

$:\implies\sf\;\sqrt{ 42\times\; 16\times\; 14\times\; 12}$

$:\implies\sf\; \sqrt{112896}$

$:\implies\large\boxed{\sf{\red{336 \; cm^2}}}$

$\rule{150}3$

Answer 2

Question:

Find area of triangle whose side is 26cm,30cm,28cm.by using heron's formula.

To find :

Area of the triangle =??

Formula used :

Heron's formula;

$s \: = ( \frac{a + b + c}{2} )$

S is the semi perimeter.

$Area \: = \sqrt{s(s - a) (s - b)(s - c)}$

Here a, b and c are the sides of the triangle.

Therefore,

a =26cm, b=30cm and c=28cm.

$s \: = \frac{26 + 28 + 30}{2} \\ s \: = \: 42$

$area \: = \sqrt{42(42 - 26)(42 - 28)(42 - 30)} \\ area \: = \sqrt{42 \times 16 \times 14 \times12} \\ area \: = \sqrt{112896} = 336 {cm}^{2}$

Therefore area of the triangle is 336 cm ².