Question

Good Morning :) A stone of mass 150g is thrown upwards with a velocity 35m/s. What is the maximum potential energy that can be gained by the stone?​

Answer 1

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↠ All Python keywords contain ⠀⠀lowercase letters only except False, ⠀⠀None and True.

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➣ An identifier is a name used to ⠀⠀identify a variable, function, class, ⠀⠀module or object.

➣ An identifier starts with a letter A to ⠀⠀Z or a to z or an underscore ⠀⠀followed by zero or more letters, ⠀⠀underscore and digits (0 to 9).

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↠ Literals or constants are those data ⠀items whose values cannot be ⠀changed program execution.

↠ They have fixed value.

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➣ Operators are special symbols ⠀⠀which perform some computation.

➣ Operands form an expression.

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Answer 2

Kinetic Energy, K.E=0.5×m×v

2

K.E=0.5×0.5×15×15=56.25J

As it has 56.25 J at the initial point as total energy, at some point X,Potential Energy(P.E.) is maximum.

Total energy=P.E.+K.E.

56.25=P.E.+K.E.

As energy is conserved total energy at point X also must be 40 J.

For P.E to be maximum K.E. must be zero.

Hence P.E.=56.25J

We can come to the conclusion that potential energy will have the maximum value at maximum height.