Question

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here is your question ➡

➡An integer from 100 through 999,inclusive is to be chosen at random. what is the probability that the number chosen will have zero at least 1 digit ?

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Answer 1

Step-by-step explanation:

FIrst we have to find the total number of integers in the set: 999-100+1 = 900.

Next we need an organized way to determine our successful options: 0 in at least 1 digit.

0 in 3 digits:  

0

0 in 2 digits:  

100, 200, 300, 400, 500, 600, 700, 800, 900 = 9

0 in 1 digit:  

  101 - 110, 120, 130, 140, . . ., 190: 18

201 - 210, 220, 230, 240, . . ., 290: 18

. . .

901-910, 920, 930, 940, . . . 990: 18

or 18*9 = 162

Now 0 +9 + 162 = 171

So the probability is

171/900 = 19/100

hope its help you

Answer 2

Step-by-step explanation:

First we have to find the total number of integers in the set: 999-100+1 = 900.

Next we need an organized way to determine our successful options: 0 in at least 1 digit.

0 in 3 digits:  

0

0 in 2 digits:  

100, 200, 300, 400, 500, 600, 700, 800, 900 = 9

0 in 1 digit:  

 

101 - 110, 120, 130, 140, . . ., 190: 18

201 - 210, 220, 230, 240, . . ., 290: 18

. . .

901-910, 920, 930, 940, . . . 990: 18

or 18*9 = 162

Now 0 +9 + 162 = 171

So the probability is

171/900 = 19/100

hope its help you

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