Question

Good morning friends please answer this question it's urgent!!!!!!​

Answer 1

$\huge\underline\green{\sf Answer:-}$

★$\large{\boxed {\sf Wave\:no. = {\frac{32R}{9}}}}$

$\huge\underline\green{\sf Solution:-}$

Let the Transition occurs in between the levels $\sf{n_{1}}$ and$\sf{n_{2}}$

Thus if ,

$\sf{n_{2}}$ > $\sf{n_{1}}$

then ,

$\large{\sf n_{1}+n_{2}=4}$

$\large{\sf n_{2}-n_{1}=2}$

$\large{\sf n_{1}=1\: and n_{2}=3}$

WE KNOW THAT :-

★$\large{\boxed{\sf {\frac{1}{\lambda}}=R×{Z}^{2}[{\frac{1}{n_{1}^{2}}}-{\frac{1}{n_{2}^{2}}]}}}$

On putting value :-

$\large\implies{\sf R×{Z}^{2}[{\frac{1}{{1}^{2}}}-{\frac{1}{{3}^{2}}}]}$

For Helium (He) Z = 2

$\large\implies{\sf R×{2}^{2}[{\frac{1}{1}}-{\frac{1}{9}}]}$

$\large\implies{\sf R×4[{\frac{8}{9}}]}$

★$\huge\red{\boxed{\sf {\frac{1}{\lambda}}={\frac{32R}{9}}}}$

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