Question

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Guys give me a answer fast.............

An Object of height 5cm is placed perpendicular to the principal axis of a concave lens is 20cm. Determine the position nature and size of the image formed using the lens formula....

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Answer 1

1-1=1
v u f
f = -10cm
u = -20cm
so,
v = -20/3*5
-20
= 5/3 = 1.66cm
the image formed is between lens and focal length. The image is diminished, virtual & erect.

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