good morning guys I am back to brainley.
(mere test chal rahe the isiliye mai brainley par online nhi tha)
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Answered by
34
Answer:
In this type of question first you have to change tan \a\a
in \bold{ \frac{sina}{cosa} }
cosa
sina
form then you have to use the suitable identity.
\bold{ tan \: a \: = \frac{sin \: a}{cos \: a} }tana=
cosa
sina
Identity used :-
\bold{{ \sin}^{2} a = 1 - {cos}^{2} a }sin
2
a=1−cos
2
a
Dear!! User kindly refer to attachment.
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