Good morning guyz!! Can anyone explain the following reaction??
23592U+10n→14456Ba+8936Kr+310n+210MeV
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23592 Uranium has to be given 10 neutron and then 14456 Barilium +8936 Kromium + 310 Neutron +210 mega Volt are produced
23592 Uranium has to be given 10 neutron and then 14456 Barilium +8936 Kromium + 310 Neutron +210 mega Volt are produced
adithyashasan007:
Thank you.. :)
mention not
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