Question

Good morning
_____________
Plz solve with full explanations.

Answer 1

QUESTION :-

नीचे की आकृति में PQ=PR और भुजा PR पर S कोई बिंदु है साबित करो कि RS <QS

ANSWER :-

if we see in,

∆PQR

it is given that,

PQ=PR

( हमें पता है कि समान भुजाओं के सम्मुख कोण समान होते हैं )

like in the attachment we have to put the angles of the triangle like angle1,angle2 ,angle3,angle4,angle5,

angle6 .

then we can so that ,

angle 4=angle 2 +angle 3

so, angle 4 is greater than angle 3.

now QRS ,

=> QS AND RS

=> angle 4 is greater than angle 3

=> QS is is greater than RS

=> so,RS is <QS ( BY ALT.ANGLE )

HOPE IT HELP U

Answer 2

Answer:

heya ji..inbox kro ..please