Math, asked by jaibirchahal, 9 months ago

Solve for x:-
log2x + log6 = 0

Answers

Answered by subha9935
1

Answer:

log 6 is 0.778

therefore log 2 x is -0.778.

=> log 2 n = 0.778 ( n = x^-1)

=> 1/log n 2 = 0.778

=> log n 2 = 1/0.778

=> log n 2 = 1.285

=> log 10 2 × log n 10 = 1.285

=> 0.301 × ( 1/ Log 10 n ) = 1.285

=> log 10 n = 0.2342

=> 10 ^ 0.2342 = n

=> x = 1/ 10^ 0.2342

=> x = 10^ -0.2342

in the calculator this is approximately 0.5832

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