grade 10th plz it's urgent
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here is your answer....
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khushi9196:
thanks for brainliest....
welcome
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BY PYTHAGORAS THEOREM ,
AC^2=BC^2+AB^2
13^2 =5^2+AB^2
169-25 = AB^2
144=AB^2
12 = AB
NOW ,
TAN THETA = PERPENDICULAR / BASE
SO, PERPENDICULAR(BC) / BASE(AB)
BC / AB = 5 / 12
HOPE THIS HELPS YOU
PLZ MARK ME BRAINLIEST
AC^2=BC^2+AB^2
13^2 =5^2+AB^2
169-25 = AB^2
144=AB^2
12 = AB
NOW ,
TAN THETA = PERPENDICULAR / BASE
SO, PERPENDICULAR(BC) / BASE(AB)
BC / AB = 5 / 12
HOPE THIS HELPS YOU
PLZ MARK ME BRAINLIEST
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