Grade: X (July 30) Assignment (Teacher Graded) Topic: Exercise of area of triangle and parallelogram – 5 Solve this question & submit the answer within August 1 ABCD is a parallelogram, P is any point on the diagonal BD. Prove that ∆APD = ∆CPD ∆APD + ∆CPB = 12 the parallelogram ABCD in area.
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Explanation:
Let the measure of each of the other two angles be.
In a quadrilateral, the sum of all four angles is 360°.
Therefore, each equal angle of the quadrilateral measures 80
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Explanation:
let the measure of each of the other two angles
be360'
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