Question

Gram equivalent weight of feso4.(nh4)2so4

Answer 1

No. of electrons lost per molecule = 1 (Fe2+ oxidises to Fe3+)
Molar mass of FeSO4.(NH4)2SO4 = 252
Equivalent mass = Molar mass/n factor=252/1
                                                                  =252 

Answer 2

Answer: 71 g

Explanation: Gram equivalent weight is the weight in grams of the compound which combines with one gram of hydrogen or eight grams of oxygen.

Gram equivalent weight is equal to ratio of gram molecular weight to the valency factor.

Valency factor (n) for salts is the total number of positive charge or total number of negative charge.

Thus${\text {gram equivalent weight}}=\frac{\text {Molecular weight}}{valency}$

The molecular mass of  $FeSO_4.(NH_4)_2SO_4$  = 284 g/mole

$FeSO_4.(NH_4)_2SO_4\rightarrow Fe^{2+}+2SO_4^{2-}+2NH_4^+$

n = total positive or total negative ions in solution = 2 + 2 = 4

Thus${\text {gram equivalent weight}}=\frac{284}{4}=71g$