Question

Gram equivalent weight of feso4.(nh4)2so4.6h2o

Answer 1

gram equivalent = Molecular mass / valency factor
.
so for complex compound... valency factor=3
so,
gram equivalent = M/3

Answer 2

Answer : The gram equivalent weight of Mohr's salt is, 98 g/eq

Solution :

The formula of Mohr's salt is, $FeSO_4.(NH_4)_2SO_4.6H_2O$

The molecular mass of Mohr's salt = 392 g/mole

Now we have to calculate the gram equivalent weight of Mohr's salt.

Formula used :

$\text{Equivalent weight}=\frac{\text{Molecular mass}}{n}$

where,

Mohr's salt, $FeSO_4.(NH_4)_2SO_4.6H_2O$ is disassociated into their ions,

$FeSO_4.(NH_4)_2SO_4.6H_2O\rightarrow Fe^{2+}+2SO_4^{2-]+2NH_4^++6H_2O$

n = total positive or total negative ions in solution = 2 + 2 = 4

Now put all the given values in the above formula, we get the equivalent weight.

$\text{Equivalent weight}=\frac{392g/mole}{4}=98g/eq$

Therefore, the gram equivalent weight of Mohr's salt is, 98 g/eq