Question

Greatest number of three digits which divisible by 23 is​

Answer 1

the greater 3 digit number = 999

On dividing 999 by 23 we get 10 as a remainder

999 = 23×43+10

so now subtract 10 from 999

999-10 = 989

so 989 is tge greatest 3 digit number which is divisible by 23.

if u have any doubt then ask

Answer 2

Hello ,

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986 is the greatest number of 3 digit which is divisible by 23

explanation =>

3 digit greatest number is 999

when we divide 23 by 999 then we get remainder 13

to finding greatest number we subtract dividend from remainder

999 - 13 = 986



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