Greatest number that will divide 753 , 33, 87 leving 7 as a remainder in each case
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Answer:
Answer is 2
Step-by-step explanation:
first we subtract 7 from 753,33and87
753-7=746
33-7=26
87-7=80
Now,we find the HCF (746,26and80) :
746=26×28+18
26=18×1+8
18=8×2+2
8=2×4+0 here we get 0 so HCF we get 2
now,80=2×40+0
So,HCF (746,26and80)=2
Hence,the greatest number is 2 that divides753,33and87 leaves remainder 7 in each case.
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