Question

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que no. 20

Answer 1

2. doubled is ur answer hope it will helps you

Answer 2

One Neutral Atom of ₇N¹⁴ Contains :

❤  7 Protons

❤  7 Neutrons

❤  7 Electrons

As Electrons have Negligible Mass, They are Neglected while Calculating the Atomic Mass of an Element

Known Fact : Mass of One Proton is u

⇒ Mass of 7 Protons = 7u

Known Fact : Mass of One Neutron is u

⇒ Mass of 7 Neutrons = 7u

⇒ Mass of One ₇N¹⁴ Atom = Mass of 7 Protons + Mass of 7 Neutrons

⇒ Mass of One ₇N¹⁴ Atom = 7u + 7u

⇒ Mass of One ₇N¹⁴ Atom = 14u

Where 'u' is the unified mass which is equal to 1.66 × 10⁻²⁷ kg

Now, Given : The Mass Attributed to Electrons were Doubled

As Electron's Mass is So Negligible that even if the Mass of Electron is Doubled, It won't be a Considerable Mass. So, The Mass of Electrons is Neglected.

Given : The Mass attributed to Protons were Halved

If the Mass of the Proton is Halved then It's New Mass will be $\bf{: \frac{u}{2}}$

⇒ Mass of Seven Protons $\bf{: \frac{7u}{2}}$

New Mass of ₇N¹⁴ = Mass of 7 New Protons + Mass of 7 Neutrons

⇒ The New Mass of ₇N¹⁴ $\bf{= \frac{7u}{2} + 7u}$

⇒ The New Mass of ₇N¹⁴ = 10.5u

Change in Mass = Original Mass of ₇N¹⁴ - New Mass of ₇N¹⁴

Change in Mass = (14u - 10.5u) = 3.5u

Percentage Change in Mass $\bf{= (\frac{3.5u}{14u} \times 100)}$

Percentage Change in Mass = 25%

The Atomic Mass would become reduced by 25%